In a confidential map of an army, the following code is used to show the height & distance of the defense posts in meters. [A N G R Y C H I L D] mapped as [1 2 3 4 5 6 7 8 9 0] There was a doubt in the actual secrecy of the above code. So , this code was changed and the new code was [G L A N D Y R I C H] mapped to [1 2 3 4 5 6 7 8 9 0]. According to the previous sode the distance between the post M and R was L R G Y meters. An army officer made the mistake of reading and he found it as L R G Y according to the new code. How much less, would the actual distance be because of this mistake? [4568]

Q) In a confidential map of an army, the following code is used to show the height & distance of the defense posts in meters. [A N G R Y C H I L D] mapped as [1 2 3 4 5 6 7 8 9 0] There was a doubt in the actual secrecy of the above code. So , this code was changed and the new code was [G L A N D Y R I C H] mapped to [1 2 3 4 5 6 7 8 9 0].

According to the previous sode the distance between the post M and R was L R G Y meters. An army officer made the mistake of reading and he found it as L R G Y according to the new code. How much less, would the actual distance be because of this mistake?

Options:
A)6719 meters
B) 6179 meters
C) 6971 meters
D) 7619 meters

Answer

A) 6719 meters | Explanation:The distance between M&R according to the old code was LRGY meters. Decoding it we get the distance to be 9435 meters. Since, the army officer read the distance LRGY according to the new code, the distance came out to be 2716 meters. So the difference in the distance would be 9435 m -2716m=6719 m.

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